WS4680 Flight Status - WestJet 4680 Flight Status

WestJet flight number WS4680 is scheduled to depart Calgary(YYC) at 10:30 and arrive Kamloops(YKA) at 10:50 local time.

WestJet WS4680

Flight Status 

Flight Time  48mins

Departs Calgary International Airport
Time Month Date
N/A N/A N/A
Arrives Kamloops Airport
Time Month Date
N/A N/A N/A

WS4680Calgary International Airport to Kamloops Airport
Scheduled departure time The flight do not operate on this date requested
Origin YYC (51.131394, -114.010551)
Destination YKA (50.705447, -120.442023)
Scheduled arrival time The flight do not operate on this date requested
Departure Terminal
Arrival Terminal
Equip Boeing 737-7CT

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useful info

  • The flight WestJet distance is 454.59km (282.47) miles
  • Current time in Calgary is 18:00, May 19 2024. Current time in Kamloops is 17:00, May 19 2024. Time difference: 1.0 hours.
  • The flight WS4680 time is 48mins which departs Calgary at 10:30 (GMT -7.0) and arrives Kamloops at 10:50 (GMT -8.0).
  • Flight from Calgary to Kamloops