The price of Mid-Range Hotel (Room/Night) in Cleveland, United States is 199.10 USD
Mid-Range Hotel in Cleveland, United States
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| Currency | Code | Symbol | Value |
|---|---|---|---|
| Japanese Yen | JPY | ¥ | 20,226.3699 JPY |
| Mexican Peso | MXN | $ | 2,603.3321 MXN |
| South Korean Won | KRW | ₩ | 211,257.0460 KRW |
| Iraqi Dinar | IQD | ع.د | 231,722.5350 IQD |
| Moldovan Leu | MDL | L | 2,609.3847 MDL |
| Kyrgystani Som | KGS | лв | 9,722.9091 KGS |
| Other cities | Price | COMPARED WITH Cleveland |
|---|---|---|
| Zuni Pueblo | 181.00 USD | -9.09% |
| Zephyrhills | 181.00 USD | -9.09% |
| Zellwood | 170.14 USD | -14.55% |
| Zelienople | 166.52 USD | -16.36% |
| Zeeland | 181.00 USD | -9.09% |
| Zapata | 161.09 USD | -19.09% |
Mid-Range Hotel price comparison chart
The Mid-Range Hotel price comparison chart shows that price for Mid-Range Hotel (Room/Night) in Cleveland is % higher than the same Mid-Range Hotel price in , United States.