The price of Mid-Range Hotel (Room/Night) in Cleveland, United States is 199.10 USD
Mid-Range Hotel in Cleveland, United States
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| Currency | Code | Symbol | Value |
|---|---|---|---|
| Georgian Lari | GEL | ლ | 335.6627 GEL |
| Cuban Peso | CUP | ₱ | 4,517.0613 CUP |
| Belize Dollar | BZD | BZ$ | 396.0358 BZD |
| Bosnia-Herzegovina Convertible Mark | BAM | KM | 287.0863 BAM |
| Pound | GGP | gp | 120.1827 GGP |
| Israeli New Sheqel | ILS | ₪ | 704.9972 ILS |
| Other cities | Price | COMPARED WITH Cleveland |
|---|---|---|
| Zuni Pueblo | 181.00 USD | -9.09% |
| Zephyrhills | 181.00 USD | -9.09% |
| Zellwood | 170.14 USD | -14.55% |
| Zelienople | 166.52 USD | -16.36% |
| Zeeland | 181.00 USD | -9.09% |
| Zapata | 161.09 USD | -19.09% |
Mid-Range Hotel price comparison chart
The Mid-Range Hotel price comparison chart shows that price for Mid-Range Hotel (Room/Night) in Cleveland is % higher than the same Mid-Range Hotel price in , United States.