The price of Mid-Range Hotel (Room/Night) in Cleveland, United States is 199.10 USD
Mid-Range Hotel in Cleveland, United States
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| Currency | Code | Symbol | Value |
|---|---|---|---|
| Namibian Dollar | NAD | $ | 2,014.6133 NAD |
| Congolese Franc | CDF | Fr | 183,556.2630 CDF |
| Seychellois Rupee | SCR | ₨ | 2,409.3290 SCR |
| Swazi Lilangeni | SZL | L | 2,016.4052 SZL |
| Singapore Dollar | SGD | $ | 249.3090 SGD |
| Lithuanian Litas | LTL | Lt | 506.5064 LTL |
| Other cities | Price | COMPARED WITH Cleveland |
|---|---|---|
| Zuni Pueblo | 181.00 USD | -9.09% |
| Zephyrhills | 181.00 USD | -9.09% |
| Zellwood | 170.14 USD | -14.55% |
| Zelienople | 166.52 USD | -16.36% |
| Zeeland | 181.00 USD | -9.09% |
| Zapata | 161.09 USD | -19.09% |
Mid-Range Hotel price comparison chart
The Mid-Range Hotel price comparison chart shows that price for Mid-Range Hotel (Room/Night) in Cleveland is % higher than the same Mid-Range Hotel price in , United States.