The price of Mid-Range Hotel (Room/Night) in Cleveland, United States is 199.10 USD
Mid-Range Hotel in Cleveland, United States
Have more accurate data for the Mid-Range Hotel (Room/Night) price in Cleveland?
Please help us update it. Thank you!
| Currency | Code | Symbol | Value |
|---|---|---|---|
| Tongan Paʻanga | TOP | T$ | 363.2818 TOP |
| Euro | EUR | € | 146.6246 EUR |
| Kyrgystani Som | KGS | лв | 9,722.9091 KGS |
| Australian Dollar | AUD | $ | 218.1638 AUD |
| Bolivian Boliviano | BOB | $b | 1,375.1956 BOB |
| Maldivian Rufiyaa | MVR | ރ. | 3,062.3571 MVR |
| Other cities | Price | COMPARED WITH Cleveland |
|---|---|---|
| Zuni Pueblo | 181.00 USD | -9.09% |
| Zephyrhills | 181.00 USD | -9.09% |
| Zellwood | 170.14 USD | -14.55% |
| Zelienople | 166.52 USD | -16.36% |
| Zeeland | 181.00 USD | -9.09% |
| Zapata | 161.09 USD | -19.09% |
Mid-Range Hotel price comparison chart
The Mid-Range Hotel price comparison chart shows that price for Mid-Range Hotel (Room/Night) in Cleveland is % higher than the same Mid-Range Hotel price in , United States.